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Half its total path in last second of its fall from rest calculate the time and height of all

Answer»

the body travelled total t SECOND and the HEIGHT is H then we have1/2gt^2 = hand1/2 g(t-1) ^ 2=h/2=1/4 GT^2=>g(t^2 + 1 - 2t) = 1/2gt^2=>1/ 2gt ^2- 2gt+g=0=> 3.41As the body travelled more than 1 s so answer is 3.41sHOPE SO IT WILL HELP U....IF IT HELPS MARK AS BRAINIEST......



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