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H3C−CH=CH2+Br2(1 equiv.)CCl4−−−→Xalc. KOH−−−−−−→ΔYNaNH2−−−−−→ΔZ Z is:

Answer» H3CCH=CH2+Br2(1 equiv.)CCl4−−Xalc. KOH−−−−−ΔYNaNH2−−−−ΔZ

Z is:


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