H2O2+2KI40% yield⟶I2+2KOHH2O2+2KMnO4+3H2SO450% yield⟶K2SO4+2MnSO4+3O2+4H2O 150 mL of H2O2 sample was divided into two parts. First part was treated with KI and formed KOH required 200 mL of M2H2SO4 for complete neutralisation. Other part was treated with KMnO4 yielding 6.72 litre of O2 at 1 atm. and 273 K. Using % yeild indicated, find the volume strength of H2O2 sample used.

H2O2+2KI40% yield⟶I2+2KOHH2O2+2KMnO4+3H2SO450% yield⟶K2SO4+2MnSO4+

1.	H2O2+2KI40% yield⟶I2+2KOHH2O2+2KMnO4+3H2SO450% yield⟶K2SO4+2MnSO4+3O2+4H2O 150 mL of H2O2 sample was divided into two parts. First part was treated with KI and formed KOH required 200 mL of M2H2SO4 for complete neutralisation. Other part was treated with KMnO4 yielding 6.72 litre of O2 at 1 atm. and 273 K. Using % yeild indicated, find the volume strength of H2O2 sample used.
Answer» $H_{2} O_{2} + 2 K I 40 % y i e l d ⟶ I_{2} + 2 K O H H_{2} O_{2} + 2 K M n O_{4} + 3 H_{2} S O_{4} 50 % y i e l d ⟶ K_{2} S O_{4} + 2 M n S O_{4} + 3 O_{2} + 4 H_{2} O$ $150$ mL of $H_{2} O_{2}$ sample was divided into two parts. First part was treated with $K I$ and formed $K O H$ required $200$ mL of $\frac{M}{2} H_{2} S O_{4}$ for complete neutralisation. Other part was treated with $K M n O_{4}$ yielding $6.72$ litre of $O_{2}$ at $1$ atm. and $273$ K. Using $%$ yeild indicated, find the volume strength of $H_{2} O_{2}$ sample used.