H2O(l)→H2(g)+12O2(g) ΔH=+890.36KJ/mole What is ΔH for formation of – InterviewSolution

1.	H2O(l)→H2(g)+12O2(g) ΔH=+890.36KJ/mole What is ΔH for formation of H2O(l) from its constituent elements?
Answer» $H_{2} O_{(l)} \to H_{2 (g)} + \frac{1}{2} O_{2 (g)} Δ H = + 890.36 K J / m o l e$ What is $Δ H$ for formation of $H_{2} O_{(l)}$ from its constituent elements?

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