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Guys fast do itI will mark brinliest to 1$t answerquestion 19 ​

Answer»

Solution:

(a+b)^3 +(b+c)^3 +(c+a)^3 - 3(a+b)(b+c)(c+a)

= a^3+b^3 + 3(a^2)b + 3A(b^2) + b^3 + c^3 + 3(b^2)c + 3b(c^2) + a^3 + c^3 + 3(a^2)c + 3a(c^2) - 3(b^2)c - 3b(c^2) - 3ABC - 3a(c^2) - 3a(b^2) - 3abc - 3(a^2)b - 3(a^2)c

= 2a^3 + 2b^3 + 2c^3 + 6abc

=2(a^3 + b^3 + c^3 + 3abc)

Hope it HELPED all...:-)


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