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Graph of specific heat at constant volume for a monoatomic gas is ____ |
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Answer»
`DELTAQ=DeltaU+PDeltaV` If `DeltaQ` is absorbed heat at constant volume `DeltaV=0` `THEREFORE C_V=((DeltaQ)/(DeltaT))V=((DeltaU)/(DeltaT))V=(DeltaU)/(DeltaT)` For an ideal monoatomic gas, `(DeltaU)/(DeltaT)=3/2 R, C_V=3/2R` |
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