1.

Graph of specific heat at constant volume for a monoatomic gas is ____

Answer»




SOLUTION :ACCORDING to first law of thermodynamics ,
`DELTAQ=DeltaU+PDeltaV`
If `DeltaQ` is absorbed heat at constant volume `DeltaV=0`
`THEREFORE C_V=((DeltaQ)/(DeltaT))V=((DeltaU)/(DeltaT))V=(DeltaU)/(DeltaT)`
For an ideal monoatomic gas,
`(DeltaU)/(DeltaT)=3/2 R, C_V=3/2R`


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