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Answer» Finding the acceleration due to gravity
the time period of SIMPLE pendulum (I) and acceleration due to gravity (g), which is expressed by RELATION,
T=2π√l/g ----------(1)
for small AMPLITUDE oscillations,
T square= 4π square l/g I.e;
g= 4πsquare l/t square-----------(2) if we know the value of L and T, we can calculate the acceleration due to gravity , g at that place.
the l-t square graph
we can plot a graph between l and T2 square by taking l along the x axis and T2 along the y axis. The graph is a straight line.(graph is given above)
from the graph,
l/t square= AB/BC=---------cm square
g= 4π square (AB/BC)
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