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GOOD MORNING GUYS ...........HAPPY RAINY DAY : ) : ) : ) : ) : ) : ) Guys give me a answer fast............. An Object of height 5cm is placed perpendicular to the principal axis of a concave lens is 20cm. Determine the position nature and size of the image formed using the lens formula.... HURRY UP GUYS..........ITS URGENT--: ) : ) : ) : ) : ) : ) : )→: ) : ) : ) |
| Answer» U FF = -10cmu = -20cm so,v = -20/3*5 -20= 5/3 = 1.66cmthe image formed is between lens and FOCAL length. The image is DIMINISHED, virtual & erect.HOPE THIS WILL HELP YOU !!!! | |