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Glucose and fructose can be distinguished by(1) Barford's tests(2) Fehling solution(3) Bendict solution(4) seliwanoff's test |
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Answer» The correct option (4) Seliwanoff's test Explanation: Seliwanoff's test: Seliwanoff's reagent is (0.5%) resorcinol in 3N Hcl. it givens red solution with fructose and sucrose but no change in colour with glucose. |
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