~—gjn (ae-&) Cos(T6-0) के =. 4&7\ e AU – InterviewSolution

1.

~—gjn (ae-&) Cos(T6-0) के =. 4&7\ e AU

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sin(90- A) = cosAcos(90-A) = sinASo, [sin(90-A)cos(90-A)] / tanA= (sinAcosA) / (sinA/cosA)= (cosA)^2

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