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Given vectors →a=12^i+√32^j, →b=√32^j+12^k and →c=^i+2^j+3^k. Then the volume of a parallelepiped with three coterminous edges as →u=(→a⋅→a)→a+(→a⋅→b)→b+(→a⋅→c)→c, →v=(→a⋅→b)→a+(→b⋅→b)→b+(→b⋅→c)→c and →w=(→a⋅→c)→a+(→b⋅→c)→b+(→c⋅→c)→c equals |
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Answer» Given vectors →a=12^i+√32^j, →b=√32^j+12^k and →c=^i+2^j+3^k. Then the volume of a parallelepiped with three coterminous edges as →u=(→a⋅→a)→a+(→a⋅→b)→b+(→a⋅→c)→c, →v=(→a⋅→b)→a+(→b⋅→b)→b+(→b⋅→c)→c and →w=(→a⋅→c)→a+(→b⋅→c)→b+(→c⋅→c)→c equals |
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