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Given three vectors `veca,vecbandvecc` each two of which are non-collinear. Further if `(veca+vecb)` is collinear with `vecc,(vecb+vecc)` is collinear with `vecaand|veca|=|vecb|=|vecc|=sqrt(2)`. Then the value of `veca.vecb=vecb.vecc+vecc.veca=`A. 3B. -3C. 0D. cannot be evaluated |
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Answer» Correct Answer - B `veca+vecb=lamdavecc` and `vecb+vecc=muveca` `therefore(lamdavecc-veca)+vecc=muveca("putting "vecb=lamdavecc-veca)` `rArr(lamda+1)vecc=(mu+1)veca` `rArrlamda=mu=-1` ltBrgt `rArrveca+vecb+vecc=0` ltBrgt `rArr|veca|^(2)+|vecb|^(2)+|vecc|^(2)+2(veca.vecb+vecb.vecc+vecc.veca)=0` `rArrveca.vecb+vecb.vecc+vecc.veca=-3` |
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