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Given the standard electrode potentials,K /K = -2.93V, Ag /Ag = 0.80V.2+Hg /Hg = 0.79V2+Mg /Mg =3+-2.37V. Cr /Cr= -0.74Varrange these metals in their increasing order of reducing power. |
| Answer» Given the standard electrode potentials,K /K = -2.93V, Ag /Ag = 0.80V.2+Hg /Hg = 0.79V2+Mg /Mg =3+-2.37V. Cr /Cr= -0.74Varrange these metals in their increasing order of reducing power. | |