Given the standard electrode potentials, K+K=−2.93 V, Ag+Ag=0.80 V H

1.	Given the standard electrode potentials, K+K=−2.93 V, Ag+Ag=0.80 V Hg2+Hg=0.79V, Mg2+Mg=−2.37 V Cr3+Cr=−0.74 V Arrange these metals in their increasing order of reducing power.
Answer» Given the standard electrode potentials, $\frac{K^{+}}{K} = - 2.93 V,$ $\frac{A g^{+}}{A g} = 0.80 V$ $\frac{H g^{2 +}}{H g} = 0.79 V,$ $\frac{M g^{2 +}}{M g} = - 2.37 V$ $\frac{C r^{3 +}}{C r} = - 0.74 V$ Arrange these metals in their increasing order of reducing power.

Given the standard electrode potentials, K+K=−2.93 V, Ag+Ag=0.80 V Hg2+Hg=0.79V, Mg2+Mg=−2.37 V Cr3+Cr=−0.74 V Arrange these metals in their increasing order of reducing power.

Answer»

Given the standard electrode potentials,

$\frac{K^{+}}{K} = - 2.93 V,$

$\frac{A g^{+}}{A g} = 0.80 V$

$\frac{H g^{2 +}}{H g} = 0.79 V,$

$\frac{M g^{2 +}}{M g} = - 2.37 V$

$\frac{C r^{3 +}}{C r} = - 0.74 V$

Arrange these metals in their increasing order of reducing power.