1.

Given that sin^-1(sin3π/4)=2π/k.Then the value of k is

Answer»

sin-1(sin 3π/4) = 2π/k
sin-1[sin(π-π/4)] = 2π/k
[ now, sin(180-theta)=sin theta]
sin-1(sinπ/4) = 2π/k
π/4 =2π/k
kπ = 8π

k = 8



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