1.

Given that: O(g)+e−→O−g ΔH=−142 kJmol−1 O(g)+2e−→O2−(g) ΔH=+702 kJmol−1 The enthalpy (heat) change for the reaction is represented by the equation- O−(g)+e−→O2− is: (correct answer +2, wrong answer -0.5)

Answer»

Given that:
O(g)+e−→O−g ΔH=−142 kJmol−1
O(g)+2e−→O2−(g) ΔH=+702 kJmol−1
The enthalpy (heat) change for the reaction is represented by the equation-
O−(g)+e−→O2− is:
(correct answer +2, wrong answer -0.5)


Discussion

No Comment Found

Related InterviewSolutions