1.

Given that in an AP D=5, s9=75 find the value of A9.

Answer»

s9=(9/2)*(2a+(9-1)D)75=(9/2)*(2a+8(5))150=9*(2a+40)50/3=2a+4050/3-40=2a-70/40=2aa=-35/40a9=a+8D=-35/40+8(5)=-35/40+40=(-35+160)/40=125/40=25/8



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