1.

given that HCP of (2539 240)=11 g Lem of(253 & 440)=253XRthen find the value

Answer»

253= 11×23440= 11×2×2××2×5LCM= 11×2^3×5×23253×R= 11×8×5×23R= 11×8×5×23/253 = 40



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