1.

Given that C(s)+O_(2)(g)rarrCO_(2)(g), DeltaH=-394 kJ2H_(2)(g)+O_(2)(g)rarr2H_(2)O(l), DeltaH=-568kJCH_(4)(g)+2O_(2)(g)rarrCO_(2)(g)+2H_(2)O(l)DeltaH=-892 kJHeat of formation of CH_(4) is

Answer»

`-70` KJ
71.8 kJ
`-244` kJ
`+782` kJ

Solution :`C+O_(2)rarrCO_(2),DeltaH=-394 kJ "...(i)"`
`2H_(2)+O_(2)rarr2H_(2)O, DeltaH=-568 kJ "...(ii)"`
`CH_(4)+2O_(2)rarrCO_(2)+2H_(2)O, DeltaH=-892 kJ "....(iii)"`
(i) + (ii) - (iii) and find the REQUIRED result.


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