Given that →A+→B=→C. If |→A|=4,|→B|=5 and |→C|=√61, then angle between →A and →B is:

Given that →A+→B=→C. If |→A|=4,|→B|=5 and |→C|=√61, then

1.	Given that →A+→B=→C. If \|→A\|=4,\|→B\|=5 and \|→C\|=√61, then angle between →A and →B is:
Answer» Given that $\to A + \to B = \to C$ . If $\| \to A \| = 4, \| \to B \| = 5$ and $\| \to C \| = \sqrt{61}$ , then angle between $\to A$ and $\to B$ is:

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Given that →A+→B=→C. If |→A|=4,|→B|=5 and |→C|=√61, then angle between →A and →B is:

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