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Given\qquad m \angle QPS = 47^\circm∠QPS=47 ∘m, angle, Q, P, S, equals, 47, degrees\qquad m \angle RPS = 3x - 38^\circm∠RPS=3x−38 ∘m, angle, R, P, S, equals, 3, x, minus, 38, degrees\qquad m \angle QPR = 7x - 95^\circm∠QPR=7x−95 ∘m, angle, Q, P, R, equals, 7, x, minus, 95, degreesFind m\angle QPRm∠QPRm, angle, Q, P, R: |
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Answer» GIVEN : m∠QPS = 47° m∠RPS = 3X - 38° m∠QPR = 7x - 95° To FIND : m∠QPR ∠QPS = ∠RPS + ∠QPR m∠QPS =m ∠RPS + m∠QPR => 47° = 3x - 38° + 7x - 95° => 47° = 10x - 133° => 10x = 47° + 133° => 10x =180° => x = 18° m∠QPR = 7x - 95° = 7(18°) - 95° = 126° - 95° = 31° Learn More 13. In Fig. 16.10, BCDE is a RECTANGLE , ED = 3.88 cm,AD= 10 cm ... CICSE)13. In Fig. 16.10, BCDE is a rectangle , ED = 3.88 cm,AD= 10 ... |
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