Given NO−2+H2O⇋HNO2+OH−, Kb=2.22×10−11 Thus, the degree of h – InterviewSolution

1.	Given NO−2+H2O⇋HNO2+OH−, Kb=2.22×10−11 Thus, the degree of hydrolysis of 0.04 M NaNO2 solution is:
Answer» Given $N O_{2}^{-} + H_{2} O ⇋ H N O_{2} + O H^{-}$ , $K_{b} = 2.22 \times 10^{- 11}$ Thus, the degree of hydrolysis of 0.04 $M$ $N a N O_{2}$ solution is:

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