1.

Given, H2S(g)→HS(g)+H(g);△Hrxn=379.6 kJmol−1 H2 (g)+S (s)→H2S (g); △H∘fH2S=−21.1 kJmol−1 H2(g)→2H(g) ; ΔH=438 kJmol−1 ΔHsublimation of S = 280 kJmol−1 Thus, △H∘fHS is

Answer»

Given, H2S(g)→HS(g)+H(g);△Hrxn=379.6 kJmol−1
H2 (g)+S (s)→H2S (g);
△H∘fH2S=−21.1 kJmol−1
H2(g)→2H(g) ; ΔH=438 kJmol−1
ΔHsublimation of S = 280 kJmol−1

Thus, △H∘fHS is


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