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Given f ex (tan x + 1) sec x dx= ex f(x) + c. |
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Answer» integration of [ e^x { f(x) + f'(x) } ] = e^x * f(x)If f(x) = sec x, then f'(x) = sec x * tan x integration of [ e^x * sec x * (tan x + 1) ] = integration of [ e^x ( sec x + sec x * tan x ) ]= integration of [ e^x { f(x) + f'(x) } ]= e^x * f(x) + C= e^x * sec x + C PLEASE HIT THE LIKE BUTTON |
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