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Given Δ ABC ~ Δ PQR, if poAB 1ar Δ-5, then findPthen find AT AABOat A POR |
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Answer» ΔABC ~ Δ PQR & AB/PQ = 1/3ar(ΔABC)/ar( Δ PQR )= AB²/ PQ² [The ratio of the areas of two similar triangles is equal to the square of the ratio of their corresponding sides.]ar(ΔABC)/ar( Δ PQR ) = 1²/3² [Given =AB/PQ = ⅓]ar(ΔABC)/ar( Δ PQR ) = 1/9Hence, the Area of ΔABC/Area of ΔPQR = 1/9 |
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