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Given , cos2^(m)thetacos2^(m+1)theta......cos2^ntheta=(sin2^(n+1)theta)/(2^(n-m+1)sin2^(m) theta)where 2^mtheta ne kpi,n,m,k in l solve the following cos""(pi)/11cos""(2pi)/11cos""(3pi)/11.....cos""(10pi)/11 is equal to |
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Answer» `-1/32` |
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