1.

Given, C(graphites)+O2(g)→CO2(g)Δr H∘=−393.5 kJ mol−1H2(g)+12 O2(g)→H2O(l);ΔrH∘=−285.8 kJ mol−2CO2(g+2H2O(l)→CH4(g)+2O2(g)ΔrH∘=+890.3 kJ mol−1Based on the above thermochemical equations, the value of Δr H∘ at 298K for the reaction, C(graphite)+2H2(g)→CH4(g) will be

Answer»

Given, C(graphites)+O2(g)→CO2(g)

Δr H∘=−393.5 kJ mol−1

H2(g)+12 O2(g)→H2O(l);

ΔrH∘=−285.8 kJ mol−2

CO2(g+2H2O(l)→CH4(g)+2O2(g)

ΔrH∘=+890.3 kJ mol−1

Based on the above thermochemical equations, the value of Δr H∘ at 298K for the reaction, C(graphite)+2H2(g)→CH4(g) will be


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