1.

Given C(graphite)+O2(g)→CO2(g);ΔfH∘=−393.5 kJmol−1H2(g)+12O2(g)→H2O(l)ΔfH∘=−285.8 kJmol−1CO2(g)+2H2O(l)→CH4(g)+2O2(g)ΔfH∘=+890.3 kJmol−1Based on the above thermochemical equations, the value of ΔfH∘ at 298 K for the reactionC(graphite)+2H2(g)→CH4(g) will be:

Answer»

Given C(graphite)+O2(g)→CO2(g);



ΔfH∘=−393.5 kJmol−1



H2(g)+12O2(g)→H2O(l)



ΔfH∘=−285.8 kJmol−1



CO2(g)+2H2O(l)→CH4(g)+2O2(g)



ΔfH∘=+890.3 kJmol−1



Based on the above thermochemical equations, the value of ΔfH∘ at 298 K for the reaction



C(graphite)+2H2(g)→CH4(g) will be:


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