1.

Given C(graphite)+O2(g)→CO2(g); ΔfH∘=−393.5 kJmol−1 H2(g)+12O2(g)→H2O(l) ΔfH∘=−285.8 kJmol−1 CO2(g)+2H2O(l)→CH4(g)+2O2(g) ΔfH∘=+890.3 kJmol−1 Based on the above thermochemical equations, the value of ΔfH∘ at 298 K for the reaction C(graphite)+2H2(g)→CH4(g) will be:

Answer»

Given C(graphite)+O2(g)→CO2(g);

ΔfH∘=−393.5 kJmol−1

H2(g)+12O2(g)→H2O(l)

ΔfH∘=−285.8 kJmol−1

CO2(g)+2H2O(l)→CH4(g)+2O2(g)

ΔfH∘=+890.3 kJmol−1

Based on the above thermochemical equations, the value of ΔfH∘ at 298 K for the reaction

C(graphite)+2H2(g)→CH4(g) will be:


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