1.

Given below are the half-cell reaction: Mn2++2e⊖→Mn; E⊖=−1.18V 2(Mn3++e⊖→Mn2+; E⊖=+1.51V The E⊖ for 3Mn2+→Mn+2Mn3+ will be: (IIT-JEE 2014)

Answer»

Given below are the half-cell reaction:
Mn2++2eMn; E=1.18V
2(Mn3++eMn2+; E=+1.51V

The E for 3Mn2+Mn+2Mn3+ will be:
(IIT-JEE 2014)




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