1.

Given a function g continuous on R such that 1∫0g(t)dt=2 and g(1)=5. If f(x)=12x∫0(x−t)2g(t)dt, then the value of (f′′′(1)−f′′(1)) is equal to

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Given a function g continuous on R such that 10g(t)dt=2 and g(1)=5. If f(x)=12x0(xt)2g(t)dt, then the value of (f′′′(1)f′′(1)) is equal to



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