Given 5 different green dyes ,four different blue dyes and three diffe

1.	Given 5 different green dyes ,four different blue dyes and three different red dyes,the number of combinations of dyes which can be chosen taking at least one green and one blue dye is
Answer» Green dyes =5 Blue dyes =4 Red dyes =3 The no of ways of choosing of at least one green and one blue is =(2⁵−1)×(2⁴−1)×2³ ⇒(32−1)×(16−1)×8 ⇒31×15×8 ⇒3720

Given 5 different green dyes ,four different blue dyes and three different red dyes,the number of combinations of dyes which can be chosen taking at least one green and one blue dye is

Answer»

Green dyes =5

Blue dyes =4

Red dyes =3

The no of ways of choosing of at least one green and one blue is =(2⁵−1)×(2⁴−1)×2³

⇒(32−1)×(16−1)×8

⇒31×15×8

⇒3720

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Given 5 different green dyes ,four different blue dyes and three different red dyes,the number of combinations of dyes which can be chosen taking at least one green and one blue dye is

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