Given, √2=1.4141 and √6=2.449, find the value of 1√3−√2−1 correct to 3 places of decimal.

Given, √2=1.4141 and √6=2.449, find the value of 1√3−√2−1

1.	Given, √2=1.4141 and √6=2.449, find the value of 1√3−√2−1 correct to 3 places of decimal.
Answer» Given, $\sqrt{2} = 1.4141 a n d \sqrt{6} = 2.449, f i n d t h e v a l u e o f \frac{1}{\sqrt{3} - \sqrt{2} - 1}$ correct to 3 places of decimal.