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| 1. |
Given 1 dm3 of 0.15 M HCL and 1 dm3 of 0.4 M HCL what is maximum volume of 0.15 M HCL which can be made by directly mixing the two solutions without adding water |
| Answer» VOLUME of FINAL mixture which makes 0.2M HCl.V*0.2 = 1*0.15 + (V-1)*0.30.2V = 0.15 +0.3V -0.30.2V = -0.15 + 0.3V-0.1V = -0.15V = 1.5 liters of 0.2M HClNotice that chloride is CL, not CL. | |