1.

Give the standard equation of hyperbola with (0,±6) and foci (0,±8).

Answer» ONG>Answer:

Given, FOCI c=8

and a= 6

we know, c²=a²+b²

64=36+b²

b² = 28

equation of given HYPERBOLA, y²/a² - x²/b² =1

y²/36 -x²/28 =1

7y² - 9x² = 252



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