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Give the standard equation of hyperbola with (0,±6) and foci (0,±8). |
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Answer» ONG>Answer: Given, FOCI c=8 and a= 6 we know, c²=a²+b² 64=36+b² b² = 28 equation of given HYPERBOLA, y²/a² - x²/b² =1 y²/36 -x²/28 =1 7y² - 9x² = 252 |
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