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Give the relationship between the wavelength of light and its angle of deviation, when it is passed through a prism. |
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Answer» Let, A = angle of prism D= angle of deviation N = refractive index λvacuum = wavelength in vacuum λmedium = wavelength in medium We know n = \(\frac{sin(\frac{A\,+\,D}{2})}{sin(\frac{A}{2})}\) n = λvacuum /λmedium so, λmedium/λvacuum x \(\frac{sin(\frac{A}{2})}{{sin(\frac{A\,+\,D}{2})}{}}\) |
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