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Answer» The characteristic test for (a) - Carbon dioxide (CO2) gas turns lime water milky when passed through it due to the formation of insoluble calcium carbonate.
- Ca(OH)2 + CO2 → CaCO3 + H2O
- Lime water Carbon Calcium dioxide carbonate
(b) - Sulphur dioxide (SO2) gas when passed through acidic potassium permanganate solution (purple in colour) turns
- it colourless because SO2 is a strong reducing agent
- 2KMnO4 + 2H2O + 5SO2→ K2SO4 + 2MnSO4 + 2H2SO4
- Potasssium Sulphur Potassium Manganese permanganate dioxide sulphate sulphate (Purple) (Colourless) (Colourless).
- Sulphur dioxide gas when passed through acidic dichromate solution (orange in colour) turns it to green because sulphur dioxide is a strong reducing agent.
(c) - The evolution of oxygen (O2) gas during a reaction can be confirmed by bringing a burning candle near the mouth of the test tube containing the reaction mixture.
- The intensity of the flame increases because oxygen supports burning.
(d) - Hydrogen (H2) gas burns with a pop sound when a burning candle is brought near it.
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