1.

Give the answer of this 4Q

Answer»

In ΔABC,

∠BAC + ∠ABC + ∠ACB = 180° (Angle sum PROPERTY of a triangle)

⇒ ∠BAC + 69° + 31° = 180°

⇒ ∠BAC = 180° − 100º

⇒ ∠BAC = 80°

∠BDC = ∠BAC = 80° (Angles in the same segment of a CIRCLE are equal)

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