1.

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Answer»

Let , 7-√5 is a rational no. is equals to r, where r is a rational no.So,7-√ 5 = r 7-r = √5.Now,LHS is a rational but RHS is an irrational.

So, our assumption was wrong; 7-√5 is not a rational no. Therefore, 7-√5 is a irrational no. Hence, proved.



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