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Give reasons : (i) SO2 is reducing while TeO2 is an oxidizing agent (ii) Nitrogen does not form pentahalide. (iii) ICI is more reactive than I2. |
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Answer» (i) SO2 is reducing agent as sulphur has d-orbital so it can easily expand its + 4 oxidation state to f 6 oxidation state and acts as reducing agent while in Te oxidation number changes from O to + 4 and electrons are reluctant to take part in bond formation due to poor shielding of d- and f -orbital. Thus lower oxidation state (+2, -2) becomes more stable and therefore TeO2 is oxidizing agent. (ii) Formation of pentahalides requires sp3d hybridization of the central atom obtained by the excitement of electrons of the central atom to empty d-orbitals. As nitrogen has no d-orbital it cannot undergo sp3d hybridization and therefore cannot form pentahalides. (iii) Inter halogen compound ICI are more reactive than halogens CI2 because X-X (I - Cl) bond in inter halogens is weaker than Cl-Cl bond in halogens except F-F bond. |
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