1.

Give reaction occurred near anode of electrolysis of sulphuric acid in electrolytic cell near inert electrode.

Answer»

Solution :* Ionization of `H_(2)SO_(4)` solution : `SO_(4)^(2-)` ions and water are NEAR anode. So, oxidation of either `SO_(4)^(2-)` or `H_(2)O` is possible.
`H_(2)SO_(4) to 2H_((aq))^(+)+So_(4(aq))^(2-)`
Oxidation of `H_(2)O`:
`2H_(2)O_((l)) to O_(2(g))+4H_((aq))^(+)+4E^(-)""E_(cell)^(THETA)=1.23V`
* Oxidation of `SO_(4)^(2-)` : Value of `E^(Theta)` of water is less and near anode species with less `E^(Theta)` value get oxidized. so, OXYGEN is produced on oxidation of water near anode. if concentration of `H_(2)SO_(4)` is more than oxidation of `SO_(4)^(2-)` is possible.
`2SO_(4(aq))^(2-) to S_(2)O_(8(aq))^(2-)+2e^(-)""E_(cell)^(Theta)=1.96V`


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