Step-by-step explanation:

\sf \large \blue{ \star \: GIVEN}⋆GIVEN

\displaystyle \sf \: Volume \: of \: cubiod \: = 2k {y}^{2} - 14KY + 20Volumeofcubiod=2ky

2

−14ky+20

\sf \large \blue{\star TO \: FIND}⋆TOFIND

\sf \: Possible \: dimensions \: of \: cubiodPossibledimensionsofcubiod

\sf \large \blue{ \star SOLUTION}⋆SOLUTION

\begin{gathered} \displaystyle \sf \: Volume \: of \: cubiod \: = 2k {y}^{2} - 14ky + 20 \\ \sf common \: the \: \: same \: TERM \\ \sf \: = 2k( {y}^{2} - 7y + 10) \\ = \sf \: 2 \TIMES k \times ( {y}^{2} - y7 + 10)\end{gathered}

Volumeofcubiod=2ky

2

−14ky+20

commonthesameterm

=2k(y

2

−7y+10)

=2×k×(y

2

−y7+10)

\begin{gathered} \sf \: volume \: of \: cubiod \: =( length) \times (breadth) \times (HEIGHT) \\ \sf \: compare \: it \: \: with \: the \: volume \: given \: we \: get \\ \end{gathered}

volumeofcubiod=(length)×(breadth)×(height)

compareitwiththevolumegivenweget

\begin{gathered} \sf \: dimensions \: of \: cubiod \: is \: \\ \sf\: 2 \: and \: \: k \: \: and \: ( {y}^{2} - 7x + 10)\end{gathered}

dimensionsofcubiodis

2andkand(y

2

−7x+10)

PLEASE MARK AS BRAINLIEST PLZZZ..