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Give expression for average value of a.c. voltage `V = V_(0) sin omega t` over interval `t = 0` to `t = (pi)/(omega)` |
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Answer» As `t = (pi)/(omega) = (1)/(2) . (2 pi)/(omega) = (1)/(2) T`, therefore, we wish to know average value of a.c. voltage over first half cycle `(0 rarr T//2)`. It is `E_(av) = (2 V_(0))/(pi)`. |
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