Give distance between consecutive nodes and antinodes in terms of wave

1.	Give distance between consecutive nodes and antinodes in terms of wavelength.
Answer» `lamda` `(lamda)/(2)` `(lamda)/(4)` `2lamda` Solution :DISTANCE of `n^(th)` node from `X =0` is `x _(N) = (nlamda)/(2)` Distance of `n^(th)` ANTINODE from `x =0` is, `x _(A) = (n + (1)/(2)) (lamda)/(2)` REQUIRED distance is, `x _(A) - x _(N) = (n + (1)/(2)) (lamda )/(2) - (n lamda )/( 2)` `therefore x_(A) - x _(N) = (lamda )/(4)`

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