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Geometric progressionThe first three terms of a geometric progression are k+4, k and 2k-15Where k is a constant find k or the first three terms |
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Answer» For a geometric progression we know that c/b=b/a b² = ac a = k+4 b = k c = 2k-15 hence k² = (k+4)(2k-15) k² = 2k²-15k+8k - 60 k²-7k-60 = 0 k²-12k+5k-60=0 k(k-12)+5(k-12)=0 (k+5)(k-12)=0 therefore k=-5 (terms are -1 -5 -25) Hope this helps plz mark as BRAINLIEST. |
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