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Gcd of 18(x³-x²+x-1) adn 12(x⁴-1) |
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Answer» Step-by-step explanation: Step 1: List the prime factors of each of the GIVEN number. For algebraic expression we have to find factors of them. Step 2: List the common factors of the given numbers or common factors. Step 3: Multiply those common factors. (5) Find the GCD of the following 2 x² - x - 1 , 4 x² + 8 x + 3 Solution: 2 x² - x - 1 = (2 x + 1) (x - 1) 4 x² + 8 x + 3 = (2X + 3) (2x + 1) |
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