gamma represents the ratio of two specific heats of a gas. For a given mass of the gas, the change in internal energy when the volume expands from V to 3V to constant pressure P is

gamma represents the ratio of two specific heats of a gas. For a given

1.	gamma represents the ratio of two specific heats of a gas. For a given mass of the gas, the change in internal energy when the volume expands from V to 3V to constant pressure P is
Answer» `(3PV)/((gamma - 1))` `(3PV)/((gamma + 1))` `(2PV)/((gamma + 1))` `(2PV)/((gamma - 1))` SOLUTION :The change in internal energy is `DeltaU = nC_(V)DELTA T` But `C_(V) = (R )/((gamma - 1)) :. Delta U = (nR Delta T)/((gamma - 1))` According to the ideal gas EQUATION, PV = nRT At constant pressure, `Pdelta V = nR Delta T` `:. Delta U = (PDelta V)/((gamma - 1)) = (P(3V - V))/((gamma- 1)) = (2PV)/((gamma - 1))`