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galvanometer has current range 20mA and voltage range of 600mV to convert this galvanometer into ammeter of range 10A shunt resistance required is |
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Answer» ong>Explanation: Given : V=750×10−3V; Ig=15×10−3A and I=25A Using, a=Igy =15×10−3750×10−3=50Ω Ig=S+aS×I 15×10−3=(S+50S)×25 ∴S=0.03Ω I hope this HELPS you to GET best ANSWER follow me fast |
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