1.

g" Ifthe 9th term of an A.P. is zero then show that the 29th term is twice the 19th term.

Answer»

Please like the solution 👍 ✔️

Let a and d respectively be the first term and common difference of the AP.

Given a9= 0

So, a + (9-1)d = 0

a+8d=0

a= -8d

Now, 29th term = a+28d

=-8d+28d

= 20d = 2 x 10d

= 2(-8d + 18d)

=2(a+18d)

= 2 x 19th term

Thus, the 29th term of the AP is twice the 19th term.



Discussion

No Comment Found