1.

Fund the solution of the following pair of linear equation. 4x+3y=10 and 7x+2y=11​

Answer»

Step-by-step explanation:

4x + 3y = 10 (eqn no. 1)

7x + 2y = 11 (eqn no. 2)

(equal the value of x or y in both the eqn)

multiplying eqn no. 1 by 2 =

2(4x + 3y = 10)

8x + 6y = 20

8x + 6y - 20 = 0 (eqn no. 3)

multiplying eqn no. 2 by 3 =

3(7x + 2y = 11)

21x + 6y = 33

21x + 6y - 33 = 0 (eqn no. 4)

ELIMINATING y by subtracting eqn no. 4 by eqn no. 3

21x + 6y - 33 - (8x + 6y - 20) = 0

21x + 6y - 33 - 8x - 6y + 20 = 0

13X - 13 = 0

13x = 13

x = 13/13

x = 1

putting the value of x in the eqn no. 1

4x + 3y = 10 (eqn no. 1)

4(1) + 3y = 10

4 + 3y = 10

3y = 10 - 4

3y = 6

y = 6/3

y = 2


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